Challenges

Reddit challenges in python language.

Files Code and Result

challenge1_easy

challenge2_easy

challenge3_easy

challenge4_easy

challenge5_easy

challenge6_easy

challenge7_easy

challenge8_easy

challenge9_easy

challenge10_easy

challenge11.easy

challenge12_easy

challenge13_easy

challenge14_easy

challenge15_easy

challenge16_easy

challenge17_easy

challenge18_easy

challenge19_easy

challenge20_easy

challenge21_easy

challenge22_easy

challenge23_easy

challenge25_easy

challenge26_easy

challenge27_easy

challenge28_easy

challenge29_easy

challenge30_easy

challenge31_easy

challenge32_easy

challenge33_easy

challenge34_easy

challenge35_easy

challenge36_easy

challenge37_easy

challenge38_easy

challenge39_easy

challenge40_easy

challenge41_easy

challenge42_easy

challenge44_easy

challenge45_easy

challenge46_easy

challenge47_easy

challenge48_easy

challenge49_easy

challenge50_easy

challenge51_easy

challenge52_easy

challenge53_easy

challenge54_easy

challenge55_easy

challenge56_easy

challenge57_easy

challenge58_easy

challenge59_easy

challenge60_easy

challenge61_easy

challenge62_easy

challenge63_easy

challenge64_easy

challenge65_easy

challenge66_Dev

challenge66_easy

challenge67_easy

challenge68_easy

challenge69_easy

challenge69_easyBonus

challenge70_easy

challenge71_easy.py

challenge72_easy

challenge73_easy

challenge74_easy

challenge76_easy

challenge77_easy

challenge79_easy

challenge80_easyone

challenge82_easy

challenge83_easy

challenge84_easy

challenge85_easy

challenge85_easybonus

challenge86_easy

challenge87_easy

challenge88_easy

challenge88_easybonus

challenge89_easy

challenge91_easy

challenge92_easy

challenge93_easy

challenge94_easy

challenge95_easy

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challenge99_easy

challenge100_easy

challenge100_easybonus

challenge101_easy

challenge101_easybonus

challenge102_easy

challenge103_easy

challenge104_easy

challenge105_easy

challenge106_easy

challenge107_easy

challenge108_easy

challenge109_easy

challenge110_easy

challenge111_easy2

challenge112_easy

challenge113_easy

challenge114_easy

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challenge146_easy

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challenge153_easy

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challenge156_easy

challenge157_easy

challenge158_easy

challenge158_easybonus

challenge159_easy

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challenge168_easy

challenge169_easy

challenge169_easybonus

challenge172_easy

challenge174_easy

challenge175_easy

challenge177_easy

challenge180_easy

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challenge184_easy

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challenge188_easy

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challenge199_easy

challenge201_easy

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challenge203_easy

challenge204_easy

challenge204_easyBonus

challenge205_easy

challenge205_easyBonu

challenge206_easy

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challenge210_easy

challenge211_easy

challenge212_easy

challenge212_easybonus

challenge213_easy

challenge214_easy

challenge215_easy

challenge216_easy

challenge217_easy

challenge218_easy

challenge218_easyBonus1

challenge218_easyBunus2

challenge219_easy

challenge220_easy.py

challenge221_easy

challenge221_easy

challenge222_easy

challenge222_easy.py

challenge223_easy

challenge226_easy

challenge226_easy

challenge228_easy.py

challenge228_easydev

challenge229_easy

challenge229_easybonus.py

challenge232_easy

challenge232_easy

challenge232_easybonus

challenge232_easybonus

challenge234_easy

challenge234_easybonus

challenge235_easy

challenge236_easy

challenge237_easy

challenge238_easy

challenge238_easybonus

challenge239_easy

challenge240_easy

challenge242_easy

challenge242_easy

challenge242_easyBonus

challenge243_easy

challenge245_easy

challenge245_easyBonus

challenge246_easy

challenge247_easy

challenge249_easy

challenge252_easy

challenge254_easy

challenge255_easy

challenge270_easy

challenge284_easy

challenge286_easy

challenge287_easy

challenge288_easy

challenge290_easy

challenge290_easybonus

challenge291_easy

challenge291_easybonus

challenge234_easy

''' I see that no [Hard] challenge was posted last week, the moderator had some challenges with getting away. Hopefully an [Easy] challenge makes up for it.
Description

A vampire number v is a number v=xy with an even number n of digits formed by multiplying a pair of n/2-digit numbers (where the digits are taken from the original number in any order) x and y together. Pairs of trailing zeros are not allowed. If v is a vampire number, then x and y are called its "fangs."

EDIT FOR CLARITY Vampire numbers were original 2 two-digit number (fangs) that multiplied to form
a four digit number. We can extend this concept to an arbitrary number of two digit numbers.
For this challenge we'll work with three two-digit numbers (the fangs) to create six digit
numbers with the same property - we conserve the digits we have on both sides of the equation.

Additional information can be found here: http://www.primepuzzles.net/puzzles/puzz_199.htm
Input Description

Two digits on one line indicating n, the number of digits in the number to factor and find
if it is a vampire number, and m, the number of fangs. Example:

4 2

Output Description

A list of all vampire numbers of n digits, you should emit the number and its
factors (or "fangs"). Example:

1260=21*60
1395=15*93
1435=41*35
1530=51*30
1827=87*21
2187=27*81
6880=86*80

Challenge Input

6 3

Challenge Input Solution

114390=41*31*90
121695=21*61*95
127428=21*74*82
127680=21*76*80
127980=20*79*81
137640=31*74*60
163680=66*31*80
178920=71*90*28
197925=91*75*29
198450=81*49*50
247680=40*72*86
294768=46*72*89
376680=73*60*86
397575=93*75*57
457968=56*94*87
479964=74*94*69
498960=99*84*60
'''


n = 2
m = 4
sett = set()

for x in range(10, 99):
    for y in range(10, 98):
        vamp = x * y
        if len(str(vamp)) == m:
            if sorted(str(x) + str(y)) == sorted(str(vamp)):
                # check for duplicates
                sett.add((y,x))
                if (x,y) in sett:
                    continue
                else:
                    print('{0}{1}{2}{3}{4}'.format(vamp, '=', x, '*', y))

Result

1395=15*93
1260=21*60
1827=21*87
2187=27*81
1530=30*51
1435=35*41
6880=80*86