Challenges

Reddit challenges in python language.

Files Code and Result

challenge1_easy

challenge2_easy

challenge3_easy

challenge4_easy

challenge5_easy

challenge6_easy

challenge7_easy

challenge8_easy

challenge9_easy

challenge10_easy

challenge11.easy

challenge12_easy

challenge13_easy

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challenge25_easy

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challenge39_easy

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challenge64_easy

challenge65_easy

challenge66_Dev

challenge66_easy

challenge67_easy

challenge68_easy

challenge69_easy

challenge69_easyBonus

challenge70_easy

challenge71_easy.py

challenge72_easy

challenge73_easy

challenge74_easy

challenge76_easy

challenge77_easy

challenge79_easy

challenge80_easyone

challenge82_easy

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challenge85_easybonus

challenge86_easy

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challenge102_easy

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challenge105_easy

challenge106_easy

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challenge110_easy

challenge111_easy2

challenge112_easy

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challenge172_easy

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challenge185_easy

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challenge204_easyBonus

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challenge214_easy

challenge215_easy

challenge216_easy

challenge217_easy

challenge218_easy

challenge218_easyBonus1

challenge218_easyBunus2

challenge219_easy

challenge220_easy.py

challenge221_easy

challenge221_easy

challenge222_easy

challenge222_easy.py

challenge223_easy

challenge226_easy

challenge226_easy

challenge228_easy.py

challenge228_easydev

challenge229_easy

challenge229_easybonus.py

challenge232_easy

challenge232_easy

challenge232_easybonus

challenge232_easybonus

challenge234_easy

challenge234_easybonus

challenge235_easy

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challenge238_easybonus

challenge239_easy

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challenge242_easyBonus

challenge243_easy

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challenge245_easyBonus

challenge246_easy

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challenge252_easy

challenge254_easy

challenge255_easy

challenge270_easy

challenge284_easy

challenge286_easy

challenge287_easy

challenge288_easy

challenge290_easy

challenge290_easybonus

challenge291_easy

challenge291_easybonus

challenge87_easy

'''
Write a function that calculates the intersection of two rectangles,
returning either a new rectangle or some kind of null value.

You're free to represent these rectangles in any way you want:
tuples of numbers, class objects, new datatypes, anything goes. For
this challenge, you'll probably want to represent your rectangles
as the x and y values of the top-left and bottom-right points.
(Rect(3, 3, 10, 10) would be a rectangle from (3, 3) (top-left) to
(10, 10) (bottom-right).)

As an example, rectIntersection(Rect(3, 3, 10 10), Rect(6, 6, 12, 12))
would return Rect(6, 6, 10, 10), while rectIntersection
(Rect(4, 4, 5, 5), Rect(6, 6, 10 10)) would return null.

'''

'''
Based on:
A.X1 < B.X2: 	true
A.X2 > B.X1: 	false
A.Y1 < B.Y2: 	true
A.Y2 > B.Y1: 	true
Intersect: 	false'''

def intersect(rect1, rect2):
    if (rect1[0] < rect2[2]) and rect1[2] > rect2[0] and \
                    rect1[1] < rect2[3] and rect1[3] > rect2[1]:
        rectangle = (rect2[0], rect2[1], rect1[2], rect1[3])
        return 'rectangle ' + str(rectangle)
    else:
        return 'no intersect!'


if __name__ == '__main__':
    rect_one = (3, 3, 10, 10)
    rect_two = (6, 6, 12, 12)
    ans = intersect(rect_one, rect_two)
    print(ans)

Result

rectangle (6, 6, 10, 10)