Challenges

Reddit challenges in python language.

Files Code and Result

challenge1_easy

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challenge207_easy

'''
For this week my theme is bioinformatics, I hope you enjoy the taste of the field
through these challenges.
Description

DNA - deoxyribonucleic acid - is the building block of every organism.
It contains information about hair color, skin tone, allergies, and more.
It's usually visualized as a long double helix of base pairs. DNA is composed
of four bases - adenine, thymine, cytosine, guanine - paired as follows: A-T and G-C.

Meaning: on one side of the strand there may be a series of bases

A T A A G C

And on the other strand there will have to be

T A T T C G

It is your job to generate one side of the DNA strand and output
the two DNA strands. Your program should take a DNA sequence as
input and return the complementary strand.
Input

A A T G C C T A T G G C

Output

A A T G C C T A T G G C
T T A C G G A T A C C G

Extra Challenge

Three base pairs make a codon. These all have different names based on what
combination of the base pairs you have. A handy table can be found here.
The string of codons starts with an ATG (Met) codon ends when a STOP codon is hit.

For this part of the challenge, you should implement functionality for translating
the DNA to a protein sequence based on the codons, recalling that every generated
DNA strand starts with a Met codon and ends with a STOP codon. Your program should
take a DNA sequence and emit the translated protein sequence, complete with a
STOP at the terminus.
Input

A T G T T T C G A G G C T A A

Output

A T G T T T C G A G G C T A A
Met Phe Arg Gly STOP

'''
import re

dna = 'A A T G C C T A T G G C'
dna_split = dna.split()
comp_strand = ''

for letter in dna_split:
    if letter == 'A':
        letter = 'T'
    elif letter == 'T':
        letter ='A'
    elif letter == 'C':
        letter = 'G'
    else:
        letter = 'C'
    comp_strand += letter + ' '
print(dna)
print(comp_strand)
print(comp_strand)


protons = {"TTT": "Phe",
    "TTC": "Phe",
    "TTA": "Leu",
    "TTG": "Leu",
    "TCT": "Ser",
    "TCC": "Ser",
    "TCA": "Ser",
    "TCG": "Ser",
    "TAT": "Tyr",
    "TAC": "Tyr",
    "TAA": "STOP",
    "TAG": "STOP",
    "TGT": "Cys",
    "TGC": "Cys",
    "TGA": "STOP",
    "TGG": "Trp",
    "CTT": "Leu",
    "CTC": "Leu",
    "CTA": "Leu",
    "CTG": "Leu",
    "CCT": "Pro",
    "CCC": "Pro",
    "CCA": "Pro",
    "CCG": "Pro",
    "CAT": "His",
    "CAC": "His",
    "CAA": "Gln",
    "CAG": "Gln",
    "CGT": "Arg",
    "CGC": "Arg",
    "CGA": "Arg",
    "CGG": "Arg",
    "ATT": "Ile",
    "ATC": "Ile",
    "ATA": "Ile",
    "ATG": "Met",
    "ACT": "Thr",
    "ACC": "Thr",
    "ACA": "Thr",
    "ACG": "Thr",
    "AAT": "Asn",
    "AAC": "Asn",
    "AAA": "Lys",
    "AAG": "Lys",
    "AGT": "Ser",
    "AGC": "Ser",
    "AGA": "Arg",
    "AGG": "Arg",
    "GTT": "Val",
    "GTC": "Val",
    "GTA": "Val",
    "GTG": "Val",
    "GCT": "Ala",
    "GCC": "Ala",
    "GCA": "Ala",
    "GCG": "Ala",
    "GAT": "Asp",
    "GAC": "Asp",
    "GAA": "Glu",
    "GAG": "Glu",
    "GGT": "Gly",
    "GGC": "Gly",
    "GGA": "Gly",
    "GGG": "Gly"
}

sequence = 'ATGTTTCGAGGCTAA'

codes = re.findall('\w{3}', sequence)
for code in codes:
    print(protons[code])

Result

A A T G C C T A T G G C
T T A C G G A T A C C G 
T T A C G G A T A C C G 
Met
Phe
Arg
Gly
STOP