Challenges
Reddit challenges in python language.
| Files | Code and Result |
|---|---|
challenge328_easy
'''
A Latin square is an n × n array filled with n different symbols, each occurring
exactly once in each row and exactly once in each column.
For example:
1
And,
1 2
2 1
Another one,
1 2 3
3 1 2
2 3 1
In this challenge, you have to check whether a given array is a Latin square.
Input Description
Let the user enter the length of the array followed by n x n numbers. Fill an
array from left to right starting from above.
Output Description
If it is a Latin square, then display true. Else, display false.
Challenge Input
5
1 2 3 4 5 5 1 2 3 4 4 5 1 2 3 3 4 5 1 2 2 3 4 5 1
2
1 3 3 4
4
1 2 3 4 1 3 2 4 2 3 4 1 4 3 2 1
Challenge Output
true
false
false
Bonus
A Latin square is said to be reduced if both its first row and its first column
are in their natural order.
You can reduce a Latin square by reordering the rows and columns. The example
in the description can be reduced to this
1 2 3
2 3 1
3 1 2
If a given array turns out to be a Latin square, then your program should reduce
it and display it.
'''
import math
def reduce_me(s):
""" lst -> str
Reduce a Latin list """
for x in range(0, len(s)):
b = s[x:] + s[:x]
print(b)
def rows_check(l, check):
row_check = False
for lst in l:
temp = sorted(lst)
if temp == check:
row_check = True
else:
return False
return row_check
def columns_check(l, a, check):
len_a = len(a)
sqrt_a = int(math.sqrt(len_a))
column_check = False
temp_list = []
for x in range(0, sqrt_a):
for y in range(0, sqrt_a):
temp = latin_list[x][y]
temp_list.append(temp)
temp_list = sorted(temp_list)
if temp_list == check:
column_check = True
temp_list = []
else:
return False
return column_check
latin_list = []
lst = ['1 2 3 4 5 5 1 2 3 4 4 5 1 2 3 3 4 5 1 2 2 3 4 5 1', '1 3 3 4',
'2 3 4 1 3 2 4 2 3 4 1 4 3 2 1']
for a in lst:
a = a.split()
len_a = len(a)
sqrt_a = int(math.sqrt(len_a))
acc = 0
temp = []
for y in range(0, len_a):
temp .append(a[y])
acc += 1
if acc == sqrt_a:
latin_list.append(temp)
temp = []
acc = 0
#print(latin_list)
check = sorted(latin_list[0])
check_string = ''.join(check)
#print(check)
#-- row_check -----------------
row_check = rows_check(latin_list, check)
if row_check:
pass
else:
print('Fail')
continue
#-- column check ----------------
column_check = columns_check(latin_list, a, check)
if column_check:
reduced = reduce_me(check_string)
print('Latin!')
else:
print('Fail')
continue
Result12345 23451 34512 45123 51234 Latin! Fail Fail |