Challenges

Reddit challenges in python language.

Files Code and Result

challenge1_easy

challenge2_easy

challenge3_easy

challenge4_easy

challenge5_easy

challenge6_easy

challenge7_easy

challenge8_easy

challenge9_easy

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challenge25_easy

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challenge64_easy

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challenge66_Dev

challenge66_easy

challenge67_easy

challenge68_easy

challenge69_easy

challenge69_easyBonus

challenge70_easy

challenge71_easy.py

challenge72_easy

challenge73_easy

challenge74_easy

challenge76_easy

challenge77_easy

challenge79_easy

challenge80_easyone

challenge82_easy

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challenge102_easy

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challenge111_easy2

challenge112_easy

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challenge169_easy

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challenge172_easy

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challenge204_easyBonus

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challenge212_easybonus

challenge213_easy

challenge214_easy

challenge215_easy

challenge216_easy

challenge217_easy

challenge218_easy

challenge218_easyBonus1

challenge218_easyBunus2

challenge219_easy

challenge220_easy.py

challenge221_easy

challenge221_easy

challenge222_easy

challenge222_easy.py

challenge223_easy

challenge226_easy

challenge226_easy

challenge228_easy.py

challenge228_easydev

challenge229_easy

challenge229_easybonus.py

challenge232_easy

challenge232_easy

challenge232_easybonus

challenge232_easybonus

challenge234_easy

challenge234_easybonus

challenge235_easy

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challenge239_easy

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challenge246_easy

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challenge270_easy

challenge284_easy

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challenge290_easy

challenge290_easybonus

challenge291_easy

challenge291_easybonus

challenge63_easy

''' Write a procedure called reverse(N, A), where N is an integer and A
is an array which reverses the N first items in the array and leaves the rest intact.

For instance, if N = 3 and A = [1,2,3,4,5], then reverse(N,A) will modify
A so that it becomes [3,2,1,4,5], because the three first items, [1,2,3],
have been reversed. Here are a few other examples:

reverse(1, [1, 2, 3, 4, 5])      -> A = [1, 2, 3, 4, 5]
reverse(2, [1, 2, 3, 4, 5])      -> A = [2, 1, 3, 4, 5]
reverse(5, [1, 2, 3, 4, 5])      -> A = [5, 4, 3, 2, 1]
reverse(3, [51, 41, 12, 62, 74]) -> A = [12, 41, 51, 62, 74]

So if N is equal to 0 or 1, A remains unchanged, and if N is
equal to the size of A, all of A gets flipped.

Try to write reverse() so that it works in-place; that is, it
uses only a constant amount of memory in addition to the list
A itself. This isn't necessary, but it is recommended.

'''
def reverse(lst, n):
    # first slice
    a = lst[:n]
    # reverse the slice
    a = a[::-1]
    # second slice
    b = lst[n:]
    # add together
    lst = a + b
    return  lst





if __name__ == '__main__':

    lst = [1, 2, 3, 4, 5]
    ans = reverse(lst, 3)
    print(ans, 3)

Result

[3, 2, 1, 4, 5] 3